In the reaction $CH_3-CH=CH_2 + H_2O + [O]$ $\xrightarrow[Acid]{KMnO_4} CH_3-CH(OH)-CH_2(OH)$ $\xrightarrow{[O]} X + HCOOH$,$X$ is:

  • A
    $CH_3-CH_2-COOH$
  • B
    $CH_3-COOH$
  • C
    $CH_3-CH_2-CHO$
  • D
    $CH_3-CH_2-OH$

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$CH_3-CH=CH_2$ $\xrightarrow{Br_2, hv (\text{low conc.})} \dots$ $\xrightarrow{Mg, \text{Dry ether}} \dots$ $\xrightarrow{CH_3-CO-CH_3, NH_4Cl} \dots$ $\xrightarrow{H^{+}, \Delta} (X)$. The end product $(X)$ of the above reaction is:

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